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18

and simply leave a triplet of graphs and a
pair of graphs. The graph will then
become, let us say, this:

[encode formula or diagram in LaTeX ??]

On testing this by the rule given in the last
lecture, we find that the graph is perfectly
possible, as it stands, but that it will
cease to be possible if more than one
of the triplet p, q, r, are true or if more
than one of the pair m, n are true, as
is obvious on inspection. This suggests that
the absurdity of the first graph is due, not
to the relation of the identity, but to the fact

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